这个我知道,我是这样写的,但总是显示“Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in C:\Inetpub\wwwroot\XXXXXX\index.php on line X ” wl_data1.inc <? $wl_data1 = mysql_connect("192.168.1.1", "root", "123"); mysql_select_db("wl_data1", $wl_data1; ?>
wl_data2.inc <? $wl_data2 = mysql_connect("192.168.1.2", "root", "123"); mysql_select_db("wl_data2", $wl_data2; ?>
wl_data3.inc <? $wl_data3 = mysql_connect("192.168.1.3", "root", "123"); mysql_select_db("wl_data3", $wl_data3; ?>
linkdata.php <? require_once("inc/wl_data1.inc"); require_once("inc/wl_data2.inc"); require_once("inc/wl_data3.inc"); ?>
index.php <? require_once("linkdata.php"); if($putin){ $res = mysql_fetch_array(mysql_query("SELECT * FROM users WHERE UserID='$text1'", $wl_data1)); if ( $res ) { echo "<script>alert('Y');</script>"; } else { echo "<script>alert('N');</script>"; } } ?> <html> <body> <form1 name="form1" method="post" action="index.php"> <input type="text" name="text1"> <input type="submit" name="putin" value="Login"> </form> </body> </html>
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